No products in the cart.

1^2+3^2+5^2+-----+(2n-1)^2=n(2n-1)(2n+1)/3

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

1^2+3^2+5^2+-----+(2n-1)^2=n(2n-1)(2n+1)/3
  • 2 answers

Iram Hasan Hasan 5 years, 9 months ago

L.H.S. Sum=1^2+2^2+---------+(2n-1)^2 =sum(2n-1)^2 =sum(4n^2+1-4n) =sum4n^2+sum(1)-sum(4n) =4[n(n+1)(2n+1)/6]+n-4n(n+1)/2 =n/3[2(n+1)(2n+1)+3-6(n+1)] =n/3[4n^2+6n+2+3-6n-6] =n/3[4n^2-1] =n/3[(2n-1)(2n+1)] =n(2n-1)(2n+1)/3

Soham Dubey 5 years, 9 months ago

Bhai rehne de
https://examin8.com Test

Related Questions

Square of 169
  • 1 answers
Express the complex number i-39
  • 0 answers
2nC2:nC3=33:10
  • 0 answers
Find the product. (4x²) (–5³)
  • 0 answers
Ch 1 ke questions
  • 1 answers
(3+i)x + (1-2i) y +7i =0
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App