No products in the cart.

Given that Root 5 is irrational …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Given that Root 5 is irrational ,prove that 2root 5-3 is an irrational no.
  • 1 answers

Tanu Kumari 5 years, 8 months ago

Let us assume on the contrary that 2√5-3 is rational. Then,there exist co-prime integer a and b such that 2√5-3=a/b 2√5=a/b+3 √5=1/2(a/b-3) ( that is a,b are integer,therefore 1/2 (a/b -3) is a rational no.) We know that, √5 is an irrational no. (given) This is contradicts the fact that √5 is irrational.So, our assumption is incorrect.Hence ,2√5 -3 us an irrational number. ??
https://examin8.com Test

Related Questions

Find the nature of quadratic equation x^2 +x -5 =0
  • 0 answers
Venu Gopal has twice
  • 0 answers
(A + B )²
  • 1 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers
Prove that root 8 is an irration number
  • 2 answers
X-y=5
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App