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Prove that (n!).(n+2)=[(n!)+(n+1)!]

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Prove that (n!).(n+2)=[(n!)+(n+1)!]
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Amos Khalthang 8 years, 1 month ago

RHS, [(n!) +(n+1)!] =(n!) +(n+1).(n!) =(n!). (1+n+1) (on taking common) =(n!). (n+2) LHS, (n!). (n+2) Therefore, RHS=LHS
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