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(1+cot A -coses A) (1+tan A+sec …

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(1+cot A -coses A) (1+tan A+sec A) =2
  • 1 answers

Natasha Jangra 5 years, 8 months ago

(1/1+cosA/1-1/sinA ) (1/1+sinA/cosA+1/cosA) [(SinA+cosA-1)÷sinA] [(cosA+sinA+1)÷cosA] [(sinA+cosA)^2 - 1]÷sinAcosA [SinA^2+ cosA^2+ 2(sinAcosA)-1]÷sinAcosA 1+ 2(sinAcosA) -1÷sinAcosA =2 Yaha pr +1 ,-1cncl ho jayenge or sinAcosA dono cncl ho jayenge or last me 2 bach jayega.. LHS=RHS
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