Compute the heat generated while transferring …

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Compute the heat generated while transferring 96000 coulumb of charge in 2 hours through a potential difference of 40 volt.

Posted by Natasha Jangra 5 years, 8 months ago

CBSE > Class 10 > Science

1 answers

Yogita Ingle 5 years, 8 months ago

Charge given, Q = 96000 C

Time given (t) = 1 hour =60 × 60 s = 3600 s

2 hour = 2 (3600) = 7200

Voltage (V) = 40 V

We know that, current can be found out by using the formula,

{tex}\begin{array} { c } { I = \frac { Q } { t } } \\\\ { I = \frac { 96000 } { 7200 } = \frac { 80 } { 6 }= \frac { 40 } { 3 } A } \end{array}{/tex}

Amount of heat generated can be found out using the formula,

{tex}\begin{array} { c } { \mathbf { H } = \mathbf { V I t } } \\\\ { = 40 \times \frac { 40 } { 3 } \times 7200 } \\\\ { = 384000 \mathrm { J } } \\\\ { = 3.84 \times 10 ^ { 6 } \mathrm { J } } \end{array}{/tex}

Thus, the “amount of heat” generated is {tex}3.84\times10^6 J{/tex}

0Thank You

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Posted by Pandey Ji 4 months, 2 weeks ago

CBSE > Class 10 > Science