Prove that exterior angle of a …

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Posted by Pragya Ahuja 5 years, 9 months ago
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Yogita Ingle 5 years, 9 months ago
An exterior angle of a triangle is equal to the sum of its interior opposite angles.
Consider triangle ABC. ∠ACD is an exterior angle.
Through C, draw CE||BA

To prove: ∠ 1 + ∠2 = ∠ACD
Proof: ∠1 = ∠x (pair of alternate interior angles since, CE||BA)
∠2 = ∠y (pair of corresponding angles)
∠1 + ∠2 = ∠x + ∠y
i.e. ∠1 + ∠2 = ∠ACD [
∠x + ∠y = ∠ACD]
Hence proved.
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