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Prove sin(b+c)/2=cos a/2

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Prove sin(b+c)/2=cos a/2
  • 1 answers

Shivam Tiwari 5 years, 8 months ago

let a,b and c are the angles of one triangle Therefore, a+b+c=180°(A.S.P) now b+c=180°-a___(i) Divide (i) by 2 on both sides b+c/2=90°-a/2 Now, sin (b+c/2) =sin(90-a/2) Therefore, sin(b+c/2)=cos a/2 (because sin90-thetha = cos thetha) HENCE PROVED
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