The first term of GP is …
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Yogita Ingle 5 years, 9 months ago
Let first term be a = 1; and common ratio = d;
Then,
ad² + a d^{4} = 90
=> d4 + d² - 90 = 0
=> d4 + 10d² - 9d² - 90 = 0
=> (d² - 9) (d² + 10) = 0
=> d² = 9 {Neglecting -10}
=> d = ±3 Hence, the common ratio is ±3.....
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