In a cricket match,a batswoman hits …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Harendra Singh 5 years ago
- 3 answers
Yogita Ingle 5 years ago
Let {tex}\bf{E} {/tex}be the event of hitting the boundary.
Then,
{tex}\sf P(E) = \dfrac{\sf Favourable \:outcomes}{\sf Total\:number\:of \:outcomes} = \dfrac{6}{30} = \bf{0.2}{/tex}
Now,
{tex}\underline{\bf{Probability\:of\:not\:hitting\:boundary}} :{/tex}
{tex}\sf 1-P(E) \\ \\ \implies 1-0.2 \implies \boxed{{\bf{0.8}}} {/tex}
Related Questions
Posted by Akhilesh Patidar 7 months, 1 week ago
- 0 answers
Posted by Sheikh Alfaz 1 month, 3 weeks ago
- 0 answers
Posted by T Prudhvi 4 months, 2 weeks ago
- 0 answers
Posted by Gnani Yogi 7 months, 1 week ago
- 0 answers
Posted by Savitha Savitha 7 months, 1 week ago
- 0 answers
Posted by Alvin Thomas 7 months, 1 week ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Utkarsh Oberoi 5 years ago
0Thank You