In a cricket match,a batswoman hits …
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Posted by Harendra Singh 4 years, 8 months ago
- 3 answers
Yogita Ingle 4 years, 8 months ago
Let {tex}\bf{E} {/tex}be the event of hitting the boundary.
Then,
{tex}\sf P(E) = \dfrac{\sf Favourable \:outcomes}{\sf Total\:number\:of \:outcomes} = \dfrac{6}{30} = \bf{0.2}{/tex}
Now,
{tex}\underline{\bf{Probability\:of\:not\:hitting\:boundary}} :{/tex}
{tex}\sf 1-P(E) \\ \\ \implies 1-0.2 \implies \boxed{{\bf{0.8}}} {/tex}
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Utkarsh Oberoi 4 years, 8 months ago
0Thank You