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The diameter of a roller is 84cm and length 120cm it 500 complete reviolation to move one cover 2 leval play ground of m.sq

Posted by Brajesh Bhadouria 5 years ago

CBSE > Class 09 > Mathematics

2 answers

Tiger Boos 5 years ago

T.s.a =2×22/7×42×120 =31680cm² Change = m =1584m²

0Thank You

Gaurav Seth 5 years ago

Given,
Diameter = d = 84cm
Radius = r = d/2 = 42cm
Length = l = 120 cm
T.S.A of cylinder = 2πrh
= 2 x 22/7 x 42 x 120
= 31680 cm²
Area levelled by 500 revolution = Area of playground
= 500 x 31680cm²
= 15840000 cm² [ change into m]
= 1584 m²

1Thank You

ANSWER

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CBSE > Class 09 > Mathematics