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F(x)=x^2-4x+3 Find:- alpha^4 beta^2+alpha^2beta^4

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F(x)=x^2-4x+3 Find:- alpha^4 beta^2+alpha^2beta^4

Posted by Eshaan Ali 5 years, 8 months ago

CBSE > Class 10 > Mathematics

6 answers

Anshul Soni 5 years, 8 months ago

α^4β^2+α^2β^4 =α^2β^2(α^2+β^2) =(3)^2(10) =9(10) =90

Anshul Soni 5 years, 8 months ago

αβ=3

Anshul Soni 5 years, 8 months ago

α^2+β^2=10

Anshul Soni 5 years, 8 months ago

Sorry Pehle galat type ho gaya

Anshul Soni 5 years, 8 months ago

Ans. 90

Anshul Soni 5 years, 8 months ago

α+β=4 αβ=3 Then α^2+β^2=16 We have to find α^4β^2+α^2β^4 Taking α^2β^2 common Then, α^2β^2(α^2+β^2) (αβ)^2(α^2+β^2) =(3)^2(16) =9(16) =144

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