The sum of the digit of …
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Gaurav Seth 5 years, 9 months ago
Let ,
The digit in the tens place is x
The digit in the ones place is y
The number is (10x + y)
Form equation 1 :
The sum of the digits is 9
x + y = 9
x = 9 - y
Form equation 2 :
The number is 6 times the units
10x + y = 6y
Put the two equations together:
x = 9 - y -------------------- [ 1 ]
10x + y = 6y -------------------- [ 2 ]
Find y:
Sub [ 1 ] into [ 2 ]:
10(9 - y) + y = 6y
90 - 10y + y = 6y
90 - 9y = 6y
15y = 90
y = 90 ÷ 15
y = 6
Find x:
When y = 6
x = 9 - 6
x = 3
Find the number
The number = 10x + y
The number = 10(3) + 6
The number = 36
Answer: The number is 36
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