Relation between electric field and current …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Ajay Sharma 5 years, 7 months ago
- 2 answers
Related Questions
Posted by Anterpreet Kaur 1 year, 3 months ago
- 0 answers
Posted by Aniket Mahajan 7 months, 2 weeks ago
- 0 answers
Posted by Khushbu Otti 1 year, 2 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Yogita Ingle 5 years, 7 months ago
Current density J is a vector quantity which is defined as the current flowing per unit area measured in a direction normal to the direction of flow of charge.
|J| = |I|/ A
Substituting the value of I and Vd in this equation |J| = |I|/ A ;
|J|= nAqVd / A
= nq. (qt|E|/ m)
|J| = (nq2t/ m).|E|
The vector J is parallel to the electric field vector.
In the above equation the quantity nq2t/ m is called conductivity σ.
|J| = (nq2t/ m).|E| = σ |E|
0Thank You