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The radionuclide 11C decays according to …

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The radionuclide 11C decays according to 11 11 + 6C → 5 B+e +ν : T1/2=20.3 min The maximum energy of the emitted positron is 0.960 MeV. Given the mass values: m ( 11 6C) = 11.011434 u and m ( 11 6B ) = 11.009305 u, calculate Q and compare it with the maximum energy of the positron emitted.

    • Posted by Samiksha Upadhyay 5 years, 7 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER
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