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1g of charcoal adsorbs 100ml of …

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1g of charcoal adsorbs 100ml of 0.5M CH3COOH to form a monolayer and thereby the molarity of CH3COOH reduces to 0.49M. what is the surface area of charcoal used by each molecule of acetic acid.? [surface area of charcoal =3.01*10²m²/g].... answer this..

Posted by Řøhăň Řąjpůť ✌️✊ 5 years, 10 months ago

CBSE > Class 12 > Chemistry

6 answers

Řøhăň Řąjpůť ✌️✊ 5 years, 10 months ago

jhooth bolte hue sharm nhi aati balika... oppar wale se daro. ??? jhooth limit mein bolo toh ke tumhe kuch ni aata.

Ďãřşháñăã Yadav ? ? ? 5 years, 10 months ago

aesa bhi kuch hota h.. ?? yrr kuch bhi nhi pdha maine aur boards aa gye may mein neet h.. kuch nhi aata mujhe... 11th ka aata pta nhi 12th mein masti kari h maine.. pta nhi kya likhungi. exam mein bhagwan he malik h mera abb. ??

Řøhăň Řąjpůť ✌️✊ 5 years, 10 months ago

BTW howz ur neet preparation going on. ?

Řøhăň Řąjpůť ✌️✊ 5 years, 10 months ago

??? miss darshu... all prepare for boards na.

Ďãřşháñăã Yadav ? ? ? 5 years, 10 months ago

I am answering u this question second tym. ???

Ďãřşháñăã Yadav ? ? ? 5 years, 10 months ago

➡️ 100mL of 0.5M CH3COOH contains CH3COOH =0.05 mol. ➡️ after adsorption, CH3COOH remained =0.049mol ➡️ acetic acid adsorbed =0.001mol=6.02*10 ^20 molecules ➡️ surface area of charcoal adsorbed by each molecule =3.81*10²m²/6.02*10^20 =5*10^-19m²

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