If we decrease kinetic energy 19% …
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Posted by Tanvi Singh ? 5 years, 3 months ago
- 2 answers
Yogita Ingle 5 years, 3 months ago
K= p /2m
p= square root.2mK
Decrease in Kinetic energy= 19% of K
i.e 19/100 * K = 0.19 K
Final K.E , K'= 0.81
Final momentum, p' = square rt. 2mK' = sqr. rt. 2m x 0.81K
= 0.9 square root 2mK = 0.9p
increase in p
p-p'/p x 100 = p-0.9p/p x 100 = 10%
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Beast Boy 5 years, 2 months ago
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