How to find value of cos …
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Sunil C N 8 years, 4 months ago
{tex} \cos 3\theta = 4{\cos ^3}\theta - 3\cos \theta \\ take \theta =20 \\ \frac{1}{2} = 4{x^3} - 3x \\ 8{x^3} - 6x-1=0 {/tex}
solve the equation
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