In a cyclic quadrilateral ABCD, if …
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Posted by Anil Sharma 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
WE have,
∠B - ∠D = 60o (i)
Since, ABCD is a cyclic quadrilateral
Then,
∠B+ ∠D = 180o (ii)
Adding (i) and (ii), we get
∠B - ∠D + ∠B + ∠D = 60o + 180o
2 ∠B = 240o
∠B = 120o
Put value of ∠B in (ii), we get
120o + ∠D = 180o
∠D = 60o
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