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In a cyclic quadrilateral ABCD, if (‹B-‹D)=60°, show that the smaller of the two is 60°

Posted by Anil Sharma 5 years, 2 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 5 years, 2 months ago

WE have,

∠B - ∠D = 60^o (i)

Since, ABCD is a cyclic quadrilateral

Then,

∠B+ ∠D = 180^o (ii)

Adding (i) and (ii), we get

∠B - ∠D + ∠B + ∠D = 60^o + 180^o

2 ∠B = 240^o

∠B = 120^o

Put value of ∠B in (ii), we get

120^o + ∠D = 180^o

∠D = 60^o

0Thank You

ANSWER

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