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Factorise x^3-3x^2-9x-5

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Factorise x^3-3x^2-9x-5

Posted by Tushar Patel 5 years, 10 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 5 years, 10 months ago

P(x) = x³ - 3x² - 9x - 5

Factors of 5 = 1,5,-1,-5

p(1) = 1³- 3 x (1)² - 9 x (1) - 5

= 1 -3 - 9 - 5

= 1 - 17 = - 16 ≠ 0

p(-1) = (-1)³ x 3 x (-1)² - 9 x (-1) -5

= -1 - 3 + 9 - 5 = -9 + 9 = 0

p(-1) =0

∴ (x+1) is a factor of p(x)

p(x) ÷ (x+1)

x³ - 3x² - 9x - 5 ÷ x + 1

= x²- 4x - 5

x² - 4x - 5

= x² - 5x + 1x - 5

= x ( x - 5) + 1 ( x - 5)

= ( x - 5) ( x + 1)

1Thank You

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CBSE > Class 09 > Mathematics