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If ad will not be equal …

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If ad will not be equal bc,then prove that the equation (a2 +b2) x2 + 2(ac +bd) x + (c2+d2) = 0 has no real roots
  • 2 answers

Manani Chaudhary 6 years, 1 month ago

Here we have A=a2+b2 B=2(ac+bd) C=a2+d2 We have the formula b2-4ac So,(2(ac+bd)2-4×a2+b2×c2+d2 (4a2c2+4b2d2-4(a2c2+b2c2+a2d2+b2d2) 4a2c2+4b2d2-4a2c2-4b2c2-4a2d2-4b2d2. -4b2c2-4a2d2 -4(b2c2-a2d2) Here roots are negative so these are imaginary not real . Hence proved

Suji 335 6 years, 1 month ago

Apply the formula b^2 - 4ac
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