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1÷a+b+c=1÷a+1÷b+1÷x

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1÷a+b+c=1÷a+1÷b+1÷x
  • 1 answers

Manani Chaudhary 6 years, 1 month ago

Here we have 1/a+b+c=1/a+1/b+1/x So by shifting x terms to one side 1/a+b+c-1/x=1/a+1/b By taking the LCM of both the sides x-(a+b+x)/x(a+b+x)=a+b/ab x-a-b-x/x(a+b+x)=a+b/ab (x-x=0) -a-b/x(a+b+x)=a+b/ab. -(a+b) -(a+b)/x(a+b+x)=a+b/ab. (-(a+b)=(a+b) ( -1=1) -1/x(a+b+x)=1/ab Cross multiply -ab=x(a+b+x) -ab=xa+xb+x2 By shifting -ab to the other side x2+xa+xb+ab By taking common x(x+a)+b(x+a) (x+a) (x+b) So x=-a or x=-b
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