No products in the cart.

Drive expression for time period of …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Drive expression for time period of simple pendulum using dimensional analysis ,given that time period depends on effective lenght (l) of simple pendulum and gravitational acceleration (g).
  • 2 answers

Knowledge Time 6 years, 1 month ago

T=kL^a g^b . M^0•L^0•T^1=L^a•L^bT^-2b . L^0=L^a+b=> 0=a+b_eq1 . T^1=T^-2b =>1=-2b =>b=-1/2' On putting it in eq 1 . 0=a-1/2 =>1/2=a Therefore the formula for time period is T=√l/√g● I tried my best to explain it properly But I think it is complicated to understand

Jashan Deep Kaur 6 years, 1 month ago

T = 2π /w T=2πl√g/l T= 2π√l/g
https://examin8.com Test

Related Questions

√kq,qpower2 R2
  • 0 answers
1dyne convert to S.I unit
  • 1 answers
2d+2d =
  • 1 answers
Ch 1 question no. 14
  • 0 answers
Project report
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App