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Drive expression for time period of …

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Drive expression for time period of simple pendulum using dimensional analysis ,given that time period depends on effective lenght (l) of simple pendulum and gravitational acceleration (g).

    • Posted by Karnail Singh 5 years, 9 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Knowledge Time 5 years, 9 months ago

    T=kL^a g^b . M^0•L^0•T^1=L^a•L^bT^-2b . L^0=L^a+b=> 0=a+b_eq1 . T^1=T^-2b =>1=-2b =>b=-1/2' On putting it in eq 1 . 0=a-1/2 =>1/2=a Therefore the formula for time period is T=√l/√g● I tried my best to explain it properly But I think it is complicated to understand

    0Thank You

    Jashan Deep Kaur 5 years, 9 months ago

    T = 2π /w T=2πl√g/l T= 2π√l/g

    0Thank You

    ANSWER
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