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The greatest number which on dividing 1659 and 2036 leaves remainders 8 and 4 respectively

Posted by Farhan Akhtar 5 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Abhi Mittal 5 years, 7 months ago

127

1Thank You

Yogita Ingle 5 years, 7 months ago

Since,Remainders are 8 and 4

In the given question,

Greatest required number = H.C.F of (1659 - 8) and (2037 - 5)

= H.C.F of 1651 and 2032

= 127

0Thank You

Janvi Aggarwal 5 years, 7 months ago

Remainders are 8 and 4 1659-8=1651 2036-4=2032 HCF of 1651 and 2032 is 127 =>the greatest no. is 127

0Thank You

ANSWER

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CBSE > Class 10 > Mathematics