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prove thatMV^2/R+h=GMm/(r+h)^2

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prove thatMV^2/R+h=GMm/(r+h)^2
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Knowledge Time 5 years, 9 months ago

F=mv^2/R+h. _eq.1. (Centripital force) F=GMm/(R+h)^2. _eq.2 From eq 1 and 2 Mv^2/r+h=GMm/(r+h)^2 I hope it is understandible
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