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A wire of uniform cross section …

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A wire of uniform cross section and length 'l' has a resistance of 16 ohm. It is cut into four equal parts. Each part is stretched uniformly to initial length and all four stretched parts are connected in parallel. Calculate the total resistance of the combination so formed. Assume that stretching of wire does not cause any change in the density of its material?

    • Posted by Mayank 007 5 years, 10 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Pooja Deora 5 years, 10 months ago

    New resistance of each wire will be r= n^2R R=4. (16/4) Wire should be 4 times strectched so n=4 r=4×4×4=64 Net resistance=64/4 =16

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