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Explain 3 newton law from calculas …

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Explain 3 newton law from calculas method

    • Posted by Deep Royal 5 years, 9 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anu Negi 5 years, 9 months ago

    First law of newton a=dv/dt adt=dv Differenciating both side a[t]^t1-t2=[v]^v-u a[t-0]=[v-u] at=v-u V=u+at Second law of newton v=dx/dt. [v=u+at] u+at=dx/dt udt+atdt=dx Differenciating both side u[t]^t-0+a[t^2]^t-0=[x]^x-0 u[t-0]+a[t^2-0/2]=[x-0] ut+1/2at^2=x. Wherex=displacement x=ut+1/2at^2

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