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2cos^2θ-1÷sinθcosθ=cotθ-tanθ

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2cos^2θ-1÷sinθcosθ=cotθ-tanθ
  • 1 answers

Aadya Singh 6 years, 2 months ago

LHS - 2cos^2theta - (cos^2 theta + sin^2 theta) / sintheta × cos theta
=> cos^2 theta - sin^2 theta / sin theta × cos theta
=> [cos^2 theta/sin theta × cos theta ] - [sin^2 theta/ sin theta × cos theta ]
=> (cos theta / sin theta) - (sin theta / cos theta)
=> cot theta - tan theta...
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