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From Chapter thermodynamic Q. Find the …

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From Chapter thermodynamic Q. Find the process C = Cv+R
  • 2 answers

Anu Negi 5 years, 9 months ago

Cp=Cv+R (Cp=[dq/dt]p),(Cv=[dq/dt]v) So using first law of thermodynamics dq=du+dw Dividing both side by dt dq/dt=du/dt+dw/dt. dq=mL,dw=pdv at constant volume [dq/dt]v=[du/dt]v+[dw/dt]v [dq/dt]v=[du/dt]v+[pdv/dt]v Take constant term outside the bracket [dq/dt]v=[du/dt]v+p[dv/dt]v Cv=[du/dt]v+0 Cv=du/dt....................... 1 At constant pressure [dq/dt]p=[du/dt]p+[dw/dt]p Cp=[du/dt]p+[pdv/dt]p........................2 From ideal gas equation Pv=nRt n=1 for 1mole Pv=Rt At constant p R=pdv/dt Putting this value pdv/dt in eq 2 Cp=Cv+R R=Cp-Cv. Mayer's formula

Prakrati Aggarwal 5 years, 9 months ago

Plz reply
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