An object of 2 cm placed …
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Yogita Ingle 5 years, 11 months ago
Given,Height of object h1= 2cm
Object distance u= -20 cm
Focal length of concave mirror f= -10 cm
To find:
Distance of screen = Image distance v=?
Height of image h2=?
We know that mirror formula is:
1/v = 1/u = 1/f
Substituting the given values in the formula:
1/v + 1/(-20) = 1/(-10)
1/v = 1/(-10) + 1/20
1/v= 10/-200
v= -200/10= -20cm
Screen should be placed at distance 20 cm from mirror in order to obtain sharp image
In other words, screen should be placed at distance 20+20 = 40 cm from the object in order to obtain sharp image.
Image will be formed in front of the mirror, i.e. real.
Magnification = -image distance/object distance
Magnification= -(-20)/(-20)
Magnification=-1
Also,Height of image = - (Height of object)
This means that image is of same size as the object but it is inverted.
1Thank You