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A straight wire carrying current of …

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A straight wire carrying current of 12A is bent into a semicircular arc of rafius 2cm. Consider the magnetic field at the centre of the arc.

Posted by Akanksha Singh 5 years, 10 months ago

CBSE > Class 12 > Physics

1 answers

Abdeali Najmi 5 years, 10 months ago

The magnetic field at the center of the arc is Explanation: Given that, Current = 12 A Radius of arc = 2 cm We know that, The magnetic field at the center of the arc is B=u°I/4r 4πx10^-7×12A/4×2×10^-2m B=1.88×10^-4T Hence, the magnetic field at the center of the arc is

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