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x+y+z =0 show that xcube+ ycube+zcube=3xyz

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x+y+z =0 show that xcube+ ycube+zcube=3xyz
  • 1 answers

Yashraj Kumar 4 years, 9 months ago

x+y+z=0 x+y=-z (x+y)3=(-z3) x3+y3+3xy(x+y)=-z3 As x+y=-z => x3+y3+3xy(-z)=-z3 x3+y3-3xyz=-z3 x3+y3+z3=3xyz Hence proved Have a good day ?
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