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A parallel plate capacitor is charged …

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A parallel plate capacitor is charged by a battery, which is then disconnected. A dielectric slab is then inserted in the space between the plates. Explain what changes, if any, occur in the values of (i) capacitance. (ii) potential difference between the plates. (iii) electric field between the plates. (iv) the energy stored in the capacitor.

Posted by Ruby Sharma 5 years, 10 months ago

CBSE > Class 12 > Physics

1 answers

Aryan Bhavsar 5 years, 10 months ago

(i)KC (ii)V/K (iii)Q/Aε0 (iv)1/2×CV/K

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