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Find the area of the quadrilateral …

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Find the area of the quadrilateral ABCD, the co-ordinates of whose vertices are A(-3,2)B, (5,4)C,(7,-6)D,(-5,-4)
  • 6 answers

M.......... Duhan 5 years, 11 months ago

In ABC=1/2{-3(4+6)+5(-6-2)+7(2-4)} =1/2{-3*10+5*-8+7*-2}=42 sq.unit???? Now in ACD=38 sq.unit ..........so,area of quadrilateral=42+38=80 sq.unit.??

Anshika - 5 years, 11 months ago

How the answer is 80

Megha Agarwal 5 years, 11 months ago

80

Anshika - 5 years, 11 months ago

☹️?

Anshika - 5 years, 11 months ago

Thank you But the answer is 80

Piyush Kr.?? 5 years, 11 months ago

66
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