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In an AP of 50 term's …

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In an AP of 50 term's the sum of first 10 terms is 210 and the sum of last 15 terms is 2565. Find the A.P.

    • Posted by Ankit Bhardwaj 5 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Pradum Gurjar 5 years, 11 months ago

    Sn=n/2[2a+(n-1)d] S10=10/2[2a+(10-1)d] 210=5[2a+9d] By transposing 210÷5=2a+9d 2a+9d=42••••••(1) Last 15th term=50-15 =35 S35=2565 S35=35/2[2a+(n-1)d] 2565=35/2[2a+(35-1)d] 2565=35a+34d•••••(2) By elimination

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