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The angle of elivation of a …

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The angle of elivation of a jet plane from a point p on the ground is 60 . After a flight of 15 seconds the angle of elevation changes to 30 . If the jet plane is flying at a constant height of 1500√3 find the speed of the plane

    • Posted by Ayush Kumar 5 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Yogita Ingle 5 years, 11 months ago

    Let height of air craft = h = 1500√3 and ground distance= d
    Then we have tan 60 = h/d
                                 √3 = 1500√3/d
                             ⇒  d =1500
    The ground distance is  1500m
    Let the  ground distance after 15 second is d1
      We have tan 30 =1500 √3/d1
                  ⇒  1/√3 = 1500√3/d1
                 ⇒     d1 = 4500
    The ground distance is 4500m
    The plane has traveled d1-d = 4500-1500=3000 m
    Plane has traveled  3000 m  in 15 sec.
    Hence the speed = distance/time
                               = 3000/15
                               = 200 m/s   or  200*3600/1000 =720 km/h
    Speed of Jet plane is 720 km/h

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