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1+secA by secA=sin^2A by my 1-cosA

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1+secA by secA=sin^2A by my 1-cosA

    • Posted by Jishnu N Gopi 5 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Broken Buddy 5 years, 11 months ago

    Solving LHS
    (1+secA)/secA × (1-cosA)
    (1/secA+1)(1-cosA)
    (CosA+1)(1-cosA)
    1-cos²A
    = sin²A = RHS

    0Thank You

    Broken Buddy 5 years, 11 months ago

    To prove 1+secA/secA = sin²A/1-cosA ,or
    (1+secA)(1-cosA)/secA=sin²A

    1Thank You

    ANSWER
    https://examin8.com Test

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