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Find the HCF of (81 and …

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Find the HCF of (81 and 237) and express it as a linear combination of (81 and 273) that is HCF of ( 81 , 273) =81x + 237y for some integer x and y?
  • 2 answers

Shreya ... 5 years, 11 months ago

237=81×2+75
81=75×1+6
75=6×12+3
6=3×2+0 .....so, HCF will be 3.
3=75-6×12◆75-(81-75×1)×12◆75+75×12-81×12◆75(1+12)-81×12◆75×12-81×12◆(237-81×2)×13-81×2◆237×13-81×2×13-81×12◆237×13-81(26+12)◆237×13-81×38◆81×(-38)+237×13◆81x+237y...hence, x will be -38 and y will be 13

Shreya ... 5 years, 11 months ago

X=-38and y=13
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