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A solid cube has been cut into two cuboids of equal volumes. Find the ratio of TSA of one of the cuboids to that to the given cube.?

Posted by Gopesh Kawatra 5 years, 1 month ago

CBSE > Class 09 > Mathematics

2 answers

Abhinav Soni 5 years, 1 month ago

When this cube is cutted into two cuboids then, [As we know volume of cuboid is -> 2*(l*b+b*h+h*l)] Let one of those cuboid be x and another be y . Now, for the ratio of their TSA=> = volume of x cuboid/volume of y cuboid = 2*(l*b+b*h+h*l)/2*(l*b+b*h+h*l) Therefore now when we cancel out each of them so the results will be, = 1/1 = 1: 1

0Thank You

Yogita Ingle 5 years, 1 month ago

The surface area of a cub is 6*(area of one face) = 6LW
The volume of a cube is LWH
acube = 6LW

to make two equal cuboids, we cut the cube in half through its height - LW(.5H)
The surface area of the cuboid is
base + top + four sides
LW + LW + 4(.5HL)
2LW + 2LH
acuboid = 2L(W+H)

so the ratio of the cube to the cuboid is
acube : acuboid
6LW : 2L(W+H)
now, the important part, since we started with a cube L = W = H, so we can simplify
6LL : 2L(L+L)
6L² : 2L(2L)
6L²: 4 L²
6:4
3:2

0Thank You

ANSWER

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