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Two protons of equal Kinetic energies …

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Two protons of equal Kinetic energies enter a region of uniform magnetic field. the first Proton enters normal to the field direction while the second enters at 30 degree to the field direction name the trajectories follow by them.

    • Posted by Sneha Singh 5 years, 10 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Aayush Singh 5 years, 10 months ago

    For 1st proton: F= qvBsin90° Fmax=qvB For 2nd proton F=qvBsin30° =qvB/root3

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