Find the number of natural numbers …
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Yogita Ingle 5 years, 3 months ago
As the numbers are divisible by both 2 and 5,so their last digit will always be 0. hence the series are 110,120,130,....,990
here a=110,d=10,an=990
an=a+(n-1)d
990=110+(n-1)10
(n-1)10=880
n-1=88
n=88+1
n=89.
thus the number of natural numbers between 102 and 998 which are divisible by both 2 and 5 is 89.
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