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An airoplane left 30 min later …

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An airoplane left 30 min later than the scheduled time and in order to reach its destination 1500km away in time it increases its speed by 250km/h from usual speed . Find usual speed
  • 14 answers

Nandini Shukla 5 years, 11 months ago

Thanks

Aseem Mahajan 5 years, 11 months ago

Solve the equation and get the answeer.

Aseem Mahajan 5 years, 11 months ago

1500×250/x -125 = x/2 => x²/2 = 375000 -125x

Aseem Mahajan 5 years, 11 months ago

Then put y =1500/x (as xy =1500)

Aseem Mahajan 5 years, 11 months ago

250y-x/2=125 not 0

Aseem Mahajan 5 years, 11 months ago

Wsit last 3 steps are wrong !! I sm so sorry!

Aseem Mahajan 5 years, 11 months ago

After solving u get x = 500√3 , so the ysual speed u let as x is 500√3 kmph

Aseem Mahajan 5 years, 11 months ago

Put y = 1500/x , (as u get before xy=1500)

Aseem Mahajan 5 years, 11 months ago

Then u get xy -x/2 +250 y -125 =xy Cancel xy , u get 250y -x/2=0

Aseem Mahajan 5 years, 11 months ago

Remember to take time in hours

Aseem Mahajan 5 years, 11 months ago

So , (x+250)(y-1/2) = xy

Aseem Mahajan 5 years, 11 months ago

Fhe speed is increased and time decreased , but the distance will be same , i e, xy

Aseem Mahajan 5 years, 11 months ago

Then the distance = xy = 1500 km

Aseem Mahajan 5 years, 11 months ago

Let the speed of aeroplane be x and normal time to cover the distance be y
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