If the distances of P(x,y) from …

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Posted by Aayush Kumar Chandrawanshi 5 years, 11 months ago
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Yogita Ingle 5 years, 11 months ago
Considering AZ = ZB, that means {tex}A Z^{2}=Z B^{2}{/tex}
{tex}(x-5)^{2}+(y-1)^{2}=(x+1)^{2}+(y-5)^{2}{/tex}
Squaring both the sides we get the factors and then simplifying them we get:
{tex}x^{2}+25-10 x+y^{2}+1-2 y=x^{2}+1+2 x+y^{2}+25-10 y{/tex}
12x = 8y
3x = 2y
Hence proved
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