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What is the smallest number when …

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What is the smallest number when divided by 35,56 and 91 leaving a remainder 7 in each case

    • Posted by Ekta Tiwari 6 years, 2 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Yogita Ingle 6 years, 2 months ago

    The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91

    35 = 5 x 7
    56 = 2 x 2 x 2 x 7
    91 = 7 x 13

    LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640

    The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

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