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The conductivity of 0.001M acetic acid …

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The conductivity of 0.001M acetic acid is 4 ×10^-5 S/cm . calculate the dissociating constant of acetic acid.if molar conductivity at infinite dilution for acetic acid is 390 S cm^2 m/mol
  • 2 answers

Yuvraj Singh 5 years, 11 months ago

λ= k × 1000/C = 40 λ°=390 α= λ/λ°=0.1025 Ka = Cα^2/1-α= 1.18 × 10^-5

Yuvraj Singh 5 years, 11 months ago

1.18 × 10^-5
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