Sin 6 theta + cos 6 theta Taking lhs:- (Sin cube theta) square + (cos cube theta )square By using identity a cube + b cube is equal to a + b whole cube minus 3 ab into a + b So (Sin square theta )cube + (cos square theta) cube = (sin square theta + cos square theta) whole cube - 3 sin square theta cos square theta ( sin square theta + cos square theta) So 1- 3 sin square theta cos square theta L.H.S =R.H.S. H.P

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