Find the HCF of 36,96,120

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Find the HCF of 36,96,120

Posted by Worlds Top10#### 5 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Jagdish 5 years, 4 months ago

36=2×2×3×3 96=2×2×2×2×2×3 120=2×2×2×3×5 Therefore HCF(36,96,120)=2×2×3=12

0Thank You

Dinesh Kumar Dwivedi 5 years, 4 months ago

By Euclid's division lemma on 36 and 96 a=bq+r , where r is equal to or greater than 0 and smaller than b Since 96 is greater than 36 Therefore a= 96 and b= 36 Now, 96=36×2+24 36=24×1+12 24=12×2+0 Since 12 is the last divisore therefore 12 is HCF of 36 and 96 Now, we will take HCF of 12 and 120 By Euclid's division lemma a=bq+r, where r is equal to or greater than 0 and smaller than b Since 120 is greater than 12 Therefore a= 120 and b= 12 Now, 120=12×10+0 Since 12 is the last divisore therefore 12 is HCF of 12 and 120. Therefore HCF of 120,96 and 36 is 12

0Thank You

Yogita Ingle 5 years, 4 months ago

On applying euclid's division Lemma for 36 and 96

96 = 36 ×2 + 24

Here, Remainder = 24≠0

So take new Dividend as 36 and divisor as 24.

36 = 24×1 +12

Here, Remainder = 12≠0

So take new Dividend as 24 and divisor as 12.

24 = 12×2 +0

Here, the Remainder = 0 and the last divisor is 12.

So, HCF of 36 and 96 is 12.

On applying euclid's division Lemma for 12 and 120

120 = 12 ×10 + 0

Here Remainder = 0

So , HCF of 36, 96 and 120 is 12.

0Thank You

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