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A battery of 9 V is …

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A battery of 9 V is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 ohm, 0.5 ohm and 12 ohm. How much current would flow through the 12 ohm resisto? Show solution with a diagram.

Posted by Rukhsar Malik 5 years, 11 months ago

CBSE > Class 10 > Science

1 answers

Aadya Singh ? 5 years, 11 months ago

Effective resistance = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 ohm.
By ohm law, I = V/R
9/13.4 = 0.67 A
All the resistance are connected in series. Hence, the current across 12 ohm resistance is 0.67A .

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