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Sin(45+A)-cos(45-A) is equal to 0.....how?

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Sin(45+A)-cos(45-A) is equal to 0.....how?

    • Posted by Dr Chhavi 5 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Dr Chhavi 5 years, 11 months ago

    It was so simple.thank you guys

    1Thank You

    Vidyotma Singh 5 years, 11 months ago

    Sin(45+A)-cos(45-A) =sin(90-(45+A))-cos(45-A) =cos(45-A)-cos(45-A) =0

    1Thank You

    Yogita Ingle 5 years, 11 months ago

      sin(45° + A) - cos(45° - A)

    =  sin(45° + A) - sin[90° - (45° - A)]

    = sin(45° + A) - sin(90° - 45° + A)

    = sin(45° + A) - sin(45° + A)

    = 0.

    1Thank You

    Vidyotma Singh 5 years, 11 months ago

    ?hmm...

    1Thank You

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    CBSE > Class 10 > Mathematics
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    CBSE > Class 10 > Mathematics
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