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Sin(6O°+ θ)-Cos(30°- θ)=?

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Sin(6O°+ θ)-Cos(30°- θ)=?

Posted by Sumit Mathur 6 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Sayyed Suleman 6 years, 3 months ago

1

Bishal Bijay Naik 6 years, 3 months ago

0

Diksha ? 6 years, 3 months ago

Ans 0

Mahee Mishra 6 years, 3 months ago

Cos (30° - θ) = cos { 90° -(60° + θ)}= sin(60°+ θ) Now, Sin(60° + θ) - cos(30° - θ) = Sin(60° + θ) - sin(60°+ θ) = 0

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This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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