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The sum of an AP whose first term is a , the second term is b and the last term is c , is equal to (a+c(b+c-2a)/2(b-a).

Posted by Vp Singh 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 3 months ago

First term =a
second term =b
last term =c
common difference=(b-a)
tn =a+(n-1) d

c=a+(n-1) d

(c-a)=(n-1)(b-a)

(c-a)/(b-a)+1=n

( c+b-2a)/(b-a)=n--------------------(1)
now ,
we know sum of n terms=n/2 (first term+last term)
put equation (1)value
= (b+c-2a)/(b-a)(a+c)
hence Sn=[(b+c-2a)(c+a)/(b-a)]

1Thank You

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CBSE > Class 10 > Mathematics